Re: PHP: Ajax send()

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2008. 02. 22, péntek keltezéssel 12.03-kor germana ezt írta:
> Hi!!
> 
> Im trying to sent data to and php with Ajax, so..
> this is what im sending>_url= "table='historia'$'='$''$'string'$''&";
> 
> then i do:
> 
> _url = _url.substring(0,_url.length-1)  //quita el & de sobra al final
> var ajax = nuevoAjax();
> 	ajax.open("POST", "atrapalo_x.php", true);
> 	ajax.setRequestHeader("Content-Type",
> "aplication/x-www-form-urlencoded");
> 	ajax.send(_url);
> 	
> 	ajax.onreadystatechange = function()
> 	{
> 		if(ajax.readyState == 4)
> 		{
> 			alert(ajax.responseText)
>                         .
>                         .
>                         .
> ..............
> 
> and in the php i do:
> 
> $datafield=explode("$",str_replace("\'","'",$_POST["table"]));
> $main_table="".str_replace("'","",$datafield[0])."";
> $main_table=strtolower($main_table);
> 
> but when i do and echo $datafield[0] or echo $main_table
> 
> it returns          nothing... just blank
> 

and if you var_dump($_POST) what does it show?

greets
Zoltán Németh

> 

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