Richard is right. If you want to get where __FILE__ is exactly in, __FILE__ is the option. Else, use $_SERVER['PHP_SELF']. (And this should be what you expected) Regards, Shelley -----Original Message----- From: christoph.boget@xxxxxxxxx [mailto:christoph.boget@xxxxxxxxx] On Behalf Of Christoph Boget Sent: Thursday, December 20, 2007 10:37 PM To: PHP General Subject: Which file called the function? Let's say I have the following 3 files global.php <? function myFunc() { echo __FILE__; } ?> one.php <? include( 'global.php' ); echo 'You are in file: '; myFunc(); ?> two.php <? include( 'global.php' ); echo 'You are in file: '; myFunc(); ?> In each case, what is echoed out for __FILE__ is global.php. Apart from analyzing the debug_backtrace array, is there any way that myFunc() would display "one.php" and "two.php" respectively? thnx, Christoph -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
