On 20 Dec 2007, at 14:37, Christoph Boget wrote:
Let's say I have the following 3 files
global.php
<?
function myFunc() { echo __FILE__; }
?>
one.php
<?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?>
two.php
<?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?>
In each case, what is echoed out for __FILE__ is global.php. Apart
from
analyzing the debug_backtrace array, is there any way that myFunc()
would
display "one.php" and "two.php" respectively?
thnx,
Christoph
Hi Christoph,
I believe __FILE__ is resolved at compile time, not run-time which
means what you're seeing is expected behavior. I'm not sure how you'd
get the name of the file that a function call was made from.
Could you explain why you need this information in your application,
and perhaps someone might offer an alternative solution?
Regards,
Nilesh
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
