Re: unexpected '@' in preg_replace???

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Daniel Brown wrote:
On 10/29/07, Zoltán Németh <znemeth@xxxxxxxxxxxxxx> wrote:
hi list,

I have this code:
[snip!]
Parse error: syntax error, unexpected '@'
in /home/znemeth/public_html/test/pregreplacetest1.php(94) : regexp code
on line 1

Fatal error: preg_replace() [<a
href='function.preg-replace'>function.preg-replace</a>]: Failed
evaluating code: _nemeth@xxxxxxxxxxxxxxxx
in /home/znemeth/public_html/test/pregreplacetest1.php on line 94
[snip=again!]

    Zoltan,

    If you're using preg_replace(), where are your start and stop
characters for the pattern and subject?

    $szoveg = preg_replace('/'.$mit.'/','/'.$mire.'/',$dokumentum);

    You could otherwise try ereg_replace(); without the slashes, or do
an htmlentities($dokumentum);.


Look again and you will notice that $mit and $mire are both arrays.

Also, the starting and stopping points are in the $mit array elements.

The starting and stopping points are not allowed in the $mire array.

This was the offending line in the code. I removed the e from the modifiers list and it started working. See if you can run the code without it.

         '/<strong[^>]*>(.*?)<\/strong>/i',      // <strong>


you missed your closing option
         '/<\/?p[^>]*>/i',                           // <P>

or maybe you should have a different entry to remove the </p> and replace it with nothing.
this
         '/<p[^>]*>/i',                           // <P>
that
	 "\n\n\t",

this
         '/<\/p[^>]*>/i',                           // </P>
that
	 '',

Side note, you might want to look into using the '+' instead of the '*'.
	'+' = must be one or more
	'*' = 0 or more

In some of the cases here, I see where this can bite you in the butt later.


--
Jim Lucas

   "Some men are born to greatness, some achieve greatness,
       and some have greatness thrust upon them."

Twelfth Night, Act II, Scene V
    by William Shakespeare

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