afan pasalic wrote:
why then the code doesn't work?
the error I'm getting is: "Fatal error: Call to undefined function
solution1() in ..." even the function itself is just above the line that
calls function?
I can only guess that you're not showing us the code you're actually
running. See the example I put in another reply - that works and is
based on the code you sent.
-Stut
--
http://stut.net/
Stut wrote:
Jay Blanchard wrote:
I don't think you can put a function name in a variable and call it like
$function($var).
Yes you can - it's basically the same as variable variables.
-Stut
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