Ondra Zizka wrote:
> Hello,
>
> please look at the code bellow and tell if it does not conform to rules of
> returning a reference from a function.
> In the first method, I return reference to $sRet variable, and PHP is quiet.
> But in the second, PHP says:
>
> Notice: Only variable references should be returned by reference in
> C:\web\php_bug_reference_return.php on line 8 // return $ref =&
> $this->ReturnReference();
> (Note that the notice does not concern the first method as the notice
> appears even if I remove references from the first method.)
>
> But I am still just returning a reference to a variable,
are you? seems like your returning a reference to the result of
an expression, in both cases.
> so I guess it's
> actually correct, isn't it?
>
> Thanks for oppinions.
> Ondra Zizka
>
>
> <?php
> class A {
> function &ReturnReference(){
> $sFoo = "Hi.";
> return $sRet =& $sFoo;
> }
> function &RequireReference(){
> return $ref =& $this->ReturnReference();
> }
> }
>
> $oA = new A();
> $ref = $oA->RequireReference();
class A {
function &ReturnReference(){
$sFoo = "Hi.";
$sRet =& $sFoo;
return $sRet;
}
function &RequireReference() {
$ref =& $this->ReturnReference();
return $ref;
}
}
$oA = new A();
$ref = $oA->RequireReference();
the above runs without notices, which should show the difference
between the result of an expression and a variable that might contain it.
> ?>
>
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