Re: Finding next recored in a array

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Richard Kurth wrote:


$query = "	SELECT	day
		FROM	emailcampaign
		where	campaign_id = '$emailcampaign'
		AND	member_id = '$members_id'
	";
$DB_Change_Campaign_Results = safe_query($query);

while ( $row = mysql_fetch_array($DB_Change_Campaign_Results) ) {
	$Campaign_array[$row['day']] = $row;
}

# At this point you have arrays as values for your $Campaign_array
# So, unless $k is an array that matches a sub array of $Campaign_array
# you're never going to get a match

$k = array_search($val,$Campaign_array);

# What is $k at this point?  An int (1, 2, 3, etc...) , string (Sunday, Monday, etc...)
# Before I go any further I will need to know the above information.

if ( ($k + 1) < count($Campaign_array) ) {
	echo $Campaign_array[$k + 1];
}


--
Jim Lucas

   "Some men are born to greatness, some achieve greatness,
       and some have greatness thrust upon them."

Twelfth Night, Act II, Scene V
    by William Shakespeare

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