Hi,
$result = mysql_query("SELECT * FROM tablename WHERE
userName='$userName' AND password = '$password'");
if($rec = mysql_fetch_array($result)){
//your code
}
Try like this it may solve. It may solve your problem
Don't try to fetch the result from one single line code.
Warm Regards,
Sanjeev
http://www.sanchanworld.com/
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-----Original Message-----
From: Chris Carter [mailto:chandan9sharma@xxxxxxxxx]
Sent: Sunday, September 16, 2007 3:10 PM
To: php-general@xxxxxxxxxxxxx
Subject: php Login script issue
Hi,
Its just a login and password validation that I am trying to achieve. If the
username is correct then the person is able to view certain page, if
incorrect then he is directed elsewhere.
<?
$userid=mysql_real_escape_string($userid);
$password=mysql_real_escape_string($password);
if($rec=mysql_fetch_array(mysql_query("SELECT * FROM tablename WHERE
userName='$userName' AND password = '$password'"))){
if(($rec['userName']==$userName)&&($rec['password']==$password)){
include "../include/newsession.php";
echo "<p class=data> <center>Successfully,Logged in<br><br>
logout.php Log OUT <br><br> welcome.php Click here if your browser is not
redirecting automatically or you don't want to wait. <br></center>";
print "<script>";
print " self.location='submit-store-details.php';"; // Comment this
line if you don't want to redirect
print "</script>";
}
}
else {
session_unset();
echo "Wrong Login. Use your correct Userid and Password and Try
<br><center><input type='button' value='Retry'
onClick='history.go(-1)'></center>";
}
?>
I am getting this error when I am using this code:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
resource in thispage.php on line 37
Wrong Login. Use your correct Userid and Password and Try
Why does it show up everytime and whats wrong with mysql_fetch_array().
Please advice also if there is some other way available please help me try
that.
Thanks,
Chris
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