On Mon, August 27, 2007 1:46 am, Dotan Cohen wrote:
> On 27/08/07, Richard Lynch <ceo@xxxxxxxxx> wrote:
>> On Sun, August 26, 2007 3:41 pm, Dotan Cohen wrote:
>> > I have a string with some HTML paragraphs, like so:
>> > $text="<p>First paragraph</p>\n<p>More text</p>\n<p>Some more
>> > text</p>\n<p>End of story</p>";
>> >
>> > I'd like to add an image before the last paragraph. I know that
>> > preg_replace can replace only the first n occurrences of a string,
>> but
>> > how can I replace the _last_ occurrence of a string? My initial
>> idea
>> > was to do this:
>> > 1) Count how many times "</p>\n<p>" occurs as $n
>> > 2) Replace them all with "</p>\n<img src= alt=>\n<p>"
>> > 3) Replace $n-1 replacements back to "</p>\n<p>"
>> >
>> > Is there a cleaner way? Thanks in advance.
>>
>> If the string really really ENDS on that LAST "</p>", then you can
>> key
>> off of that:
>>
>> $story = preg_replace("|(<p>.*</p>\$|Umsi",
>> "<p>$new_paragraph</p>\n\\1", $story;
>>
>> You may have to fiddle with the DOT_ALL setting to only match the
>> true
>> end of string and not just any old "\n" within the string...
>> http://php.net/pcre
>>
>
> Thanks, Richard, I was also trying to use a regex with pre_replace and
> getting nowhere. In the manual page for strrpos, there is a
> user-comment function for finding the last occurrence of a string:
> http://il2.php.net/manual/en/function.strrpos.php#56735
>
> However, I am unable to piece 2 and 2 together.
>
> Note that I'm adding a paragraph before the last paragraph, so I'm
> searching for the last instance of "</p>\n<p>".
>
> This is what I've done to your code, but I'm unable to get much
> further:
> $text = preg_replace("|(</p>\n<p>)\$|Umsi", "</p>\n<p>Test</p>\n<p>",
> $text);
The strrpos solution might be better/easier...
$last_paragraph = strrpos($text, "</p>\n<p>");
$text = substr($text, 0, $last_paragraph - 1) . "</p>\n<p>Test" .
substr($text, $last_paragraph);
I almost always get the "- 1" bit in the wrong place, but that should
get you close enough to work it out.
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