Marcelo de Moraes Serpa wrote:
How could I iterate over the files in a directory and build a list of unique
filenames? Take the following filelist:
file1_01.jpg
file2_01.jpg
file2_02.jpg
file2_03.jpg
file3_01.jpg
file3_02.jpg
file3_03.jpg
file4_01.jpg
file4_02.jpg
file4_03.jpg
I would like to build an array like this: $names =
("file1","file2","file3","file4")
As mentioned, use array_unique(). But that'll only help once you've
built up an array of filenames (after trimming off the last bit). I
think Jay & Hamza missed the fact that the files are *already unique*.
One would be hard-pressed to store multiple files with the same name in
a directory.
So, i'm assuming your filenames wil be more like:
foo_01.jpg
foo_02.jpg
bar_01.jpg
etc. IOW, you want to perform a regexp such that you isolate the last
part to remove it before shuffling out the dupes. So:
$filenames = Array('foo_01.jpg', 'foo_02.jpg', 'bar_01.jpg',
'baz_01.jpg', 'bar_02.jpg');
$out = array_unique(preg_replace('/^([a-z]+)_[0-9]+\.jpg$/', '$1',
$filenames));
var_dump($out);
--snip--
array(3) {
[0]=> string(3) "foo"
[2]=> string(3) "bar"
[3]=> string(3) "baz"
}
--snip--
Note that if you might have uppercase letters, dashes, underscores, etc.
in the filename you'll need to modify that a bit. Something like:
'/^([a-zA-Z-_]+)_[0-9]+\.jpg$/'
If you'll have more than one file extension, replace 'jpg' with '[a-z]+'
However, the array_unique call will cause, eg. both 'bar_01.jpg' and
'bar_01.png' to output 'bar' only once, which may not be what you want.
HTH,
brian
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