Jay Blanchard wrote:
Given the string 'foo''bar''glorp' (all quotes are single quotes)I had
hoped to find a regular expression using preg_match that would return an
array containing just those words without having to go through
additional gyrations, like exploding a string to get an array. I have
only had limited luck
$theString = "'foo''bar''glorp'";
preg_match( "/\'(.*)\'/", $theString, $matches);
print_r($matches);
Array
(
[0] => 'foo''bar''glorp'
[1] => foo''bar''glorp
)
Of course $matches[0] has the entire string and $matches[1] contains the
returned string minus the leading and trailing single quote. I can
explode $matches[1] to get what I want, but it is an extra step and I am
sure that I have done this before but cannot locate the code in
question. I would like the results to be
Array
(
[0] => 'foo''bar''glorp'
[1] => foo
[2] => bar
[3] => glorp
)
That way I can use the $matches array without having to create another
array to hold the values. I feel as if I am really close on the regex to
do this, but cannot seem to find (after much head scratching and teeth
gnashing) the proper solution.
Much thanks!
2(-3) steps:
1. Make it _un_greedy (preg_* are greedy by default, so "/'(.*)'/U" will
match foo''bar''glorp, making it ungreedy (/U modifier) would make it
match just foo
2. Make it fetch _all_ matches, use preg_match_all
(3. there's no need to escape single quotes in this string :))
The following works:
preg_match_all("/'(.*)'/U", "'foo''bar''glorp'", $matches);
print_r($matches);
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