On Fri, July 13, 2007 2:15 am, Richard Lynch wrote:
> On Thu, July 12, 2007 8:29 am, Robert Cummings wrote:
>> Hmmm, I thought using an explicit cast was very self explanatory --
>> especially when the name of the cast is "array". Maybe I'm alone in
>> that
>> thought. I mean if you convert a scalar to an array what do you
>> expect
>> to get? An array with the scalar. *shrug* I can't see how it would
>> be
>> anything else.
>
> $foo = (array) 'foo';
> var_dump($foo);
>
> A couple perfectly reasonable (though wrong) outputs:
>
> #1
> array (3){
> 0 => 'f',
> 1 => 'o',
> 2 => 'o'
> );
>
> And, actually, PHP having been derived (partially) from C, one could
> almost argue this is the EXPECTED output. :-)
In retrospect, given that $foo[1] is 'o' and that you can treat $foo
JUST like an array of characters, the EXPECTED output from a C->PHP
perspective might be:
string (3) 'foo'
It already *IS* an array, to a large extent.
:-)
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