Will do. Thanks.
----- Original Message -----
From: "Jim Lucas" <lists@xxxxxxxxx>
To: "kvigor" <k3cheese@xxxxxxxxxxxxx>
Cc: <php-general@xxxxxxxxxxxxx>
Sent: Saturday, June 30, 2007 1:46 AM
Subject: Re: Selecting Rows Based on Row Values Being in Array
kvigor wrote:
Hello All,
I'm attempting to return rows from a mysql DB based on this criteria:
I have a list, in the form of an array that I need to compare against
each row
in the table. Where theres a match I need that entire row returned.
e.g. $varListof 3outOf_10Fields = array(6blue40lbs, 7orange50lbs,
8orange60lbs, 9purple70lbs);
The array contains 3 of the db row fields in 1 value. However there are
10 fields/columns in the table.
===============
what table looks like |
===============
size color weight
ROW 1 | value1 | value1 | value1 | value1 | value1 | value1 |
So how could I set up a query that would SELECT the entire row, if the
row contained $varListof 3outOf_10Fields[1].
Open to any suggestions or work arounds. I'm playing with extract() but
code is too crude to even post.
I would suggest approaching the problem with a slightly different thought.
just have the sql concat() the columns together and then compare.
something like this should do the trick
$list = array(
'6blue40lbs',
'7orange50lbs',
'8orange60lbs',
'9purple70lbs',
);
$SQL = "
SELECT *
FROM my_Table
WHERE CONCAT(value1, value2, value3) IN ('".join("','", $list)."')
";
mysql_query($SQL);
this should take, for each row in the DB, value1 + value2 + value3 and
create one string from them, then it will compare each string in the
IN (...) portion to each entry in the $list array().
Let me know if you need any further help
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