Re: IF with multiple values for a variable

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On 6/13/07, Dan Shirah <mrsquash2@xxxxxxxxx> wrote:
Okay, I know this has got to be easy but it's not working any way I try it.

When a record is selected it opens up a new page.  My query will display the
specific results based on the type of record selected.  There can be
multiple values in each if.  However I am having a brain fart in my if
statement assigning the multiple values.

Here is my if statement:

 if ($type == 'T','D','L' {
    $get_id.=" payment_request WHERE id = '$payment_id'";
    }

However this does not return ant results.
I've tried  if ($type = array('T','D','L'), if ($type == array('T','D','L'),
if ($type == 'T,D,L'), if ($type == 'T' or 'D' or 'L'

I also looked in the PHP manual for examples of if's and didn't find any
help.

I can get it to work if I create a seperate if statement for each type
condition but i would prefer to not duplicate my code just to add a seperate
$type


   Dan,

   Are you trying to do this?

<?
   if ($type == 'T' || $type == 'D' || $type == 'L') {
       $get_id.=" payment_request WHERE id = '$payment_id'";
   }
?>

--
Daniel P. Brown
[office] (570-) 587-7080 Ext. 272
[mobile] (570-) 766-8107

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