On Wed, 2007-06-06 at 11:43 -0400, Brad Fuller wrote: > Hey guys, > > I'm faced with an interesting problem, and wondering if there's an easy > solution. > > I need to strip out a domain name from a URL, and ignore subdomains (like > www) > > I can use parse_url to get the hostname. And my first thought was to take > the last 2 segments of the hostname to get the domain. So if the URL is > http://www.example.com/ > Then the domain is "example.com." If the URL is http://example.org/ then > the domain is "example.org." > > This seemed to work perfectly until I come across a URL like > http://www.example.co.uk/ > My script thinks the domain is "co.uk." > > So I added a bit of code to account for this, basically if the 2nd to last > segment of the hostname is "co" then take the last 3 segments. > > Then I stumbled across a URL like http://www.example.com.au/ > > So it occurred to me that this is not the best solution, unless I have a > definitive list of all exceptions to go off of. > > Does anyone have any suggestions? > > Any advice is much appreciated. I'm not sure about in PHP, but using the linux command: dig www.example.co.uk seems to have what you want in the Authority section. Cheers, Rob. -- .------------------------------------------------------------. | InterJinn Application Framework - http://www.interjinn.com | :------------------------------------------------------------: | An application and templating framework for PHP. Boasting | | a powerful, scalable system for accessing system services | | such as forms, properties, sessions, and caches. InterJinn | | also provides an extremely flexible architecture for | | creating re-usable components quickly and easily. | `------------------------------------------------------------' -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
