Re: Confused about how exactly to output image using imagepng function

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On 5/17/07, Dave M G <martin@xxxxxxxxxxxxx> wrote:
PHP list,

I've looked at the manual entries for imagepng() and
imagecreatetruecolor() functions for helping me to create a temporary
image for a CAPTCHA system.

However, I'm clearly messing up, as what I'm outputting is a bunch of
ASCII gibberish to the screen.

What I think I need to do in principle is first create the image with
imagecreatetruecolor(), then define it as a PNG (?), then display it.

So I've got something like this:

$image = ImageCreate($width, $height);
ImageFill($image, 0, 0, $black);
echo '<img " src="' . Imagepng($image) . '" height="' . $height . '"
width="' . $width .'" alt="captcha" />' . "\n";
ImageDestroy($image);

As mentioned, this isn't working, so there's a fundamental concept about
how PHP creates and displays images that I'm not getting.

I'm trying to output an image that, ideally, won't be stored as a file.
Or, if it has to be a temporary file, to delete it immediately after
displaying it.

What part am I not understanding?

Thank you for any advice or information.


It's quite simple, a second PHP script should generate the image, not
the same as that isn't gonna work.

as src expects an url where the source is located, and what you are
doing is that you're giving the source right there.

so you should have a second script called image.php or such with code:
$image = ImageCreate($width, $height);
ImageFill($image, 0, 0, $black);
Imagepng($image);
ImageDestroy($image);

and then in your first page like
echo '<img " src="image.php" height="' . $height . '"
width="' . $width .'" alt="captcha" />' . "\n";


Tijnema

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