Marcelo Wolfgang wrote:
Hi all,
I'm developing for my first time an upload file form which will populate
a sql insert query, I think I got everything working fine, but the data
isn't been saved on the database. Can someone help me with what I'm
doing wrong here ?
the code follow:
<?php
if (($_FILES["file"]["type"] == "application/msword")
|| ($_FILES["file"]["type"] == "application/pdf")
&& ($_FILES["file"]["size"] < 2000000))
{
if ($_FILES["file"]["error"] > 0)
{
echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
}
else
{
if (file_exists("../downloads/" . $_FILES["file"]["name"]))
{
echo $_FILES["file"]["name"] . " already exists. ";
}
else
{
move_uploaded_file($_FILES["file"]["tmp_name"],
"../downloads/" . $_FILES["file"]["name"]);
}
}
}
else
{
echo "Invalid file";
}
$title = $_POST["title"];
$filePath = "../downloads/" . $_FILES["file"]["name"];
if($_FILES["file"]["type"] == "application/pdf"){
$fileType = "pdf";
} else if ($_FILES["file"]["type"] == "application/msword"){
$fileType = "doc";
}
echo($title) . "<br />"; //outputs 'yada' ( correctly as I've typed on
the form;
echo($filePath) . "<br />"; //outputs '../downloads/66321-Estrutura.doc'
and I can check that the file is there;
echo($fileType) . "<br />"; //outputs 'doc' this is correct;
mysql_connect("localhost",$db_user,$db_pass) or die (mysql_error());;
mysql_select_db ($db_table);
$user_Query = mysql_query("INSERT INTO tb_downloads (var_title,
var_filepath, var_filetype, dt_data, bol_active) VALUES ('$title',
'$filePath','$fileType','NOW(),1)");
You have an error in your SQL statement.
You have a single quote opening just before your NOW() call.
I usually setup my query in a string before I place it in the mysql_query() command.
This way I can echo it out and see it before it get executed.
$SQL = "INSERT INTO tb_downloads (
var_title,
var_filepath,
var_filetype,
dt_data,
bol_active
) VALUES (
'$title',
'$filePath',
'$fileType',
NOW(),
1
)";
echo $SQL;
plus, just for debugging, you should add this to your query line
$user_Query = mysql_query($SQL) or die("SQL Error #[".mysql_errno()."]:<br />\n" . mysql_error());
mysql_close();
echo($user_Query) . "<br />"; //outputs nothing (? I suck at debugin
queries)
this will only output the Result pointer from mysql.
You need to use something like this:
print_r(mysql_fetch_assoc($user_Query));
you might want to look at mysql_num_rows() also. This will tell you the number of results you got
back.
Take a look at this example, it will give you all the needed parts to make this work
http://us.php.net/mysql_fetch_assoc#id5291494
header("Location:
http://www.w3ol.com.br/50congresso/adm/downloads.php";); // I know that
this won't work while I echo something on the page, but the echo is
there for debug only
?>
TIA
Marcelo Wolfgang
--
Jim Lucas
"Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them."
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