Re: Show Filename using Wildcards

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Agreed! And definitely modified my code to use basename()

    <?php
    exec("find /Users/rjohari/Documents/XFER/espi -type f -name
".$row['PHONE']."*.vox", $files);
    foreach ($files as $value) {
        echo basename($value)."<br>";
    }
    ?>

Thanks!


On 3/29/07 3:58 PM, "Tijnema !" <tijnema@xxxxxxxxx> wrote:

> On 3/29/07, Rahul Sitaram Johari <sleepwalker@xxxxxxxxxxxxxxxx> wrote:
>> Ave,
>> 
>> This Works!!
>> 
>>    <?php
>>    exec("find /Users/rjohari/Documents/XFER/espi -type f -name
>> ".$row['PHONE']."*.vox", $files);
>>    foreach ($files as $value) {
>>        echo substr($value,35)."<br>";
>>    }
>>    ?>
>> 
>> THANKS!
> 
> I recommend using basename($value) instead of substr($value,35)
> If the directory changes, the basename would still return valid
> values, while substr wouldn't
> 
> Tijnema
>> 
>> ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
>> Rahul Sitaram Johari
>> CEO, Twenty Four Seventy Nine Inc.
>> 
>> W: http://www.rahulsjohari.com
>> E: sleepwalker@xxxxxxxxxxxxxxxx
>> 
>> ³I morti non sono piu soli ... The dead are no longer lonely²
>> 
>> 
>> 
>> On 3/29/07 4:31 PM, "Peter Lauri" <lists@xxxxxxxxxxx> wrote:
>> 
>> 
>>> [Peter Lauri - DWS Asia]
>>> 
>>> Hi,
>>> 
>>> Assuming you are on a linux you could try:
>>> 
>>> exec("find /the/path/to/the/place/where/you/should/start/searching -type f
>>> -name 515515515*.ext", $files);
>>> 
>>> Then the $files will be an array with the found files matching the search.
>>> 
>>> Best regards,
>>> Peter Lauri
>>> 
>>> www.dwsasia.com - company web site
>>> www.lauri.se - personal web site
>>> www.carbonfree.org.uk - become Carbon Free
>>> 
>>> --
>>> PHP General Mailing List (http://www.php.net/)
>>> To unsubscribe, visit: http://www.php.net/unsub.php
>>> 
>> 
>> 


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