On 3/14/07, Myron Turner <turnermm02@xxxxxxx> wrote:
Richard Lynch wrote: > On Tue, March 13, 2007 6:04 pm, Jonathan Kahan wrote: > >> This did fix the problem but I am amazed that >> >> $s%$d=0 would be interpereted as a statement assigning d to 0 since >> there is >> some other stuff in front of d... I would think that would produce an >> error >> at compile time since $s%$d is an illegal variable name. Normally when >> my >> php script errors at compile time nothing will display to the screen. >> > > You still have not correctly puzzled out what $s % $d = 0 is doing... > > The = operator takes precedence, and $d is set to 0. > But why? According to the manual, the modulus operator has precedence over the equals! So shouldn't this expression resolve to: ($s % $d) = 0 which gives an error?
Might it be that it generates only an error in specific error levels? Tijnema
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