Since in PHP you don't declare variable types, PHP does its best to guess
what you mean with your values and integers have preference to strings, so
your '01' gets converted to a plain integer 1 for the comparison.
Use === (triple) equal in the comparison and it will check for both value
AND type and it won't do any type conversion.
Satyam
----- Original Message -----
From: "Arno Coetzee" <arno@xxxxxxxxxxxxxxxx>
To: "php-general" <php-general@xxxxxxxxxxxxx>
Sent: Monday, March 12, 2007 8:26 AM
Subject: Data Types Problem
Hi Guys
I seem to have a problem with data types in php
when executing the following script , i do not get the desired output.
i a pass url parameter (message) to the script.
if i pass a numeric value (1) , the script accepts it as '01' and vice
versa.
the same with 0 and '00'
here is the script:
<?php
$theMessage = $_REQUEST['message'];
echo "theMessage : '" . $theMessage . "'\n";
if ($theMessage == "01")
{
echo "message : '01'";
}else if ($theMessage == "00")
{
echo "message : '00'";
}else if (is_numeric($theMessage))
{
echo "Numeric Input : " . $theMessage;
}else
{
echo "Invalid Input";
}
?>
i presume that i am not interpreting the data types it should be
interpreted.
can anyone please help
--
Arno Coetzee
Flash Media Group
Developer
Mobile : 27 82 693 6180
Office : 27 12 430 7597
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