:| if i want link 3, $result = mysql_query("SELECT address FROM db.links WHERE link_id=3"); $foo = mysql_fetch_assoc($result); echo '<a href="'.$foo['address'].'">this is link 3</a>'; On 3/7/07, StainOnRug <StainOnRug@xxxxxxx> wrote:
Hello.. I searched for an answer on the simple quesiton but I am only finding complex answers... I simply just want to add a link in my database so when my results display you can see the information.. and when they click the link it takes them to the webpage of the article. I tried inserting examplesite.com User sees this text but when the results page shows.. it doesnt show the hyperlink.. Thank you all very much! -Darren Thanks again! -- View this message in context: http://www.nabble.com/Links-tf3366303.html#a9365950 Sent from the PHP - General mailing list archive at Nabble.com. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
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