Jay Blanchard wrote:
[snip]
if(empty($orgname)) { $formerror['orgname'] = "Optional"; }
elseif($result = ValidateString($orgname, "2")) { $formerror['orgname']
=
$result; }
if(empty($website)) { $formerror['website'] = "Optional"; }
if($result = ValidateString($website, "2")) { $formerror['website'] =
$result; }
if(empty($event)) { $formerror['event'] = "Optional"; }
if($result = ValidateString($event, "2")) { $formerror['event'] =
$result; }
[/snip]
The second condition of each if statement does not contain equality
checking, it sets the $result to ValidateString($event, "2"). That
should be
if($result == ValidateString($event, "2")) or
if($result === ValidateString($event, "2"))
What if the intension was to fail if the result of ValidateString() was
false??
Then it should be writen as such.
if ( ( $result = ValidateString($event, "2") ) !== FALSE ) {
$formerror['event'] = $result;
}
Jim Lucas
[snip]
Again, sorry to be a pain, but I just don't get it.
[/snip]
No problem Grasshopper
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php