Re: I lied, another question / problem

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# phpuser@xxxxxxxxxx / 2007-01-15 18:33:31 -0500:
> > From: Roman Neuhauser [mailto:neuhauser@xxxxxxxxxx] 
> > # phpuser@xxxxxxxxxx / 2007-01-15 16:31:32 -0500:
> > > I have file which I use for validating which includes the following
> > > function:
> > > 
> > > function invalidchar($strvalue)
> > > {
> > > 	if(!ereg("^[[:alpha:][:space:]\'-.]*$", $strvalue)) {
> > 
> > That regexp matches if $strvalue consists of zero or more 
> > ocurrences of a letter, a whitespace character, and any 
> > character whose numeric value lies between the numeric values 
> > of "'" and "." in your locale.
> > Zero or more means it also matches an empty string.
> 
> I'm still confused. This works perfectly on my other two pages with the
> exact same code. So why is it only this one page that is causing a problem? 
 
I don't know, I don't care. You have enough problems with the single
regex, let's concentrate on fixing this first.

> If I enter the word "test" in my form, without the quotes, then why is the
> fuction returning anything since this is a valid entry. Should it not only
> return a value if there is a problem.
 
I don't understand that paragraph. The regexp matches, and the function
returns *nothing* just as you programmed it.  That, of course, means
that the variable you are assigning this *nothing* gets set to
*nothing*, which, in PHP lingo, is null.

> All I want to accomplish here is to allow the user to enter a to z, A to Z,
> and /\'-_. and a space. Is there a better way to do this?

1. Do you really want to let them enter backslashes, or are you trying
   to "escape" the apostrophe?
2. Does that mean that "/\'-_." (without the quotes) and "   " (that's
   three spaces) are valid entries?

-- 
How many Vietnam vets does it take to screw in a light bulb?
You don't know, man.  You don't KNOW.
Cause you weren't THERE.             http://bash.org/?255991

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