short of playing around with the global keyword (which won't work when you call includeIt() from another function)) your pretty much stuck. basically imho you need to rethink what it is your trying to do. function have their own scope for a reason; maybe consider using an array argument like so: function incIt($file, $args = array()) { extract((array)$args); include $file; // don't forget some error checking } function includeIt($file, $args = array()) { // bla incIt($file, $args); // more bla } I broke it down into 2 functions to avoid local variables being overridden in includeIt() [by the call to extract]. Eli wrote: > Hi, > > I want to create a function that does some stuff, and then includes > another file in the place from where it was called. The idea is to run > the included file not in the function, but in the place of the caller in > the caller's environment (not in the function environment). > For example: > > <?php > function includeIt($file) { > $name = "Debora"; > trigger_error("Include START: '$file'"); > include($file); // This include should run in the environment > // of the caller, from the place it was called. > trigger_error("Include END: '$file'"); > } > > $name = "Joe"; > echo "Hello!"; > includeIt("msg.inc"); // The file should be included here, not in the > // 'includeIt' function. > // Say the file 'msg.inc' uses the $name > // variable from the caller's environment. > // In this case, I want it to say hello to Joe, > // and not to Debora. > echo "Bye!"; > ?> > > -thanks, Eli. > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php