On Wed, 2006-12-20 at 10:58 -0500, Jon Anderson wrote: > WeberSites LTD wrote: > > I'm trying to insert the number 1970324970930197 into a mysql BigInt(20) > > field. > > If I do a direct insert from mysql command prompt and select the record I > > get > > back the same number. > > > > If I do this from PHP I get back 1970324970930000. Notice that the 197 at > > the > > end is not 000. > AFAIK, PHP uses 32-bit (signed) integers, so you're stuck to values no > bigger than around 2 billion. Anything larger, and you have to store it > as a string: use a "BigInt" class, or GMP functions to do calculations. > I believe MySQL will do the right thing if you insert a string "integer" > into an integer field. Just to add... the reason the number changes is because PHP detects that it is too big and so stuffs it into a float where precision is then lost. Cheers, Rob. -- .------------------------------------------------------------. | InterJinn Application Framework - http://www.interjinn.com | :------------------------------------------------------------: | An application and templating framework for PHP. Boasting | | a powerful, scalable system for accessing system services | | such as forms, properties, sessions, and caches. InterJinn | | also provides an extremely flexible architecture for | | creating re-usable components quickly and easily. | `------------------------------------------------------------' -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
