My take:
$number = (int) $number;
if ($number < 1) $number = 1;
You could error out for < 1, or compare the original with the (int)
cast to see if PHP considers them = and error out if not, while using
the (int) cast to be SURE you have an int, or...
But a typecast and inequality test should be pretty clear and cheap.
On Wed, December 6, 2006 2:01 pm, Dotan Cohen wrote:
> How can I ensure that a variable contains a postive integer number?
> I'm currently using this code:
>
> $number=(10000-$number);
> $number=(10000-$number);
> if ( $number<1 ) { $number=1; }
>
> But I'm sure that there is a better way. What would that be?
>
> Dotan Cohen
>
> http://what-is-what.com/what_is/internet.html
> http://song-lirics.com/
>
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Some people have a "gift" link here.
Know what I want?
I want you to buy a CD from some starving artist.
http://cdbaby.com/browse/from/lynch
Yeah, I get a buck. So?
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