How can you use an array as string in the include statement and two lines lower as array? Think it echo's 'S' because it see's $lang as a string and not an array. On Tue, 05 Dec 2006 13:11:12 -0200, "Fernando M. M." <stormrider@xxxxxxxxxxxxxx> wrote: > Hi, > > I'm having a strange problem when trying to show a array after its value > was defined on a file that was included. Something like this: > > <?php > $lang = 'pt_BR'; > > include('lang/'. $lang .'/login.php'); > > echo $lang['Username']; > ?> > > On the file lang/pt_BR/login.php i have this... > > <?php > $lang['Username'] = 'Usuário'; > ?> > > But the result of the first script is 'S' (without quotes). > > If i change lang/pt_BR/login.php to > > <?php > $lang['Username'] = 'Usuário'; > > echo $lang['Username']; > ?> > > I get 'Usuário' (without quotes again). > > Why does this happens? > > Thanks, > > Fernando. > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php