afan@xxxxxxxx wrote:
hi to all,
I have table orders with primary key order_id. I have table uploaded_files
with primary key ufid and uploaded files are linked to orders by order_id
column.
I have to list all orders and uploaded files. this works fine:
$query = mysql_query("
select order_id, order_date, order_status
from orders
order by order_id desc
limit 100");
while($result=mysql_fetch_array($query))
{
echo "ID: ". $result['order_date']."|";
echo "DATE: ". $result['order_date'] ."|";
echo "STATUS: ". $result['order_status'] ."|";
echo "UPLOADED FILES: ";
$query2 = mysql_query("
select uf.file_name
from uploaded_files as uf
where uf.order_id = $result['order_id']
");
while($result2=mysql_fetch_array($query2))
{
echo $result2['file_name']."|";
}
echo "<hr>";
}
but I know there must be much better solution then this one.
thanks for any help.
-afan
Perhaps something like this: (not sure how this would play with the
limit key word, but you could play around with it...)
If you can guarantee that a record (order_id) will appear in both
tables, a simple join will work...
but if a record in table A exists but not in table B, a join will not
return that record, which is why there is a left outer join.
select o.order_id, o.order_date, o.order_status, uf.file_name
from orders o left outer join uploaded_files uf on uf.order_id = o.order_id
order by o.order_id desc
Not sure if mysql supports this..??
select * from (select o.order_id, o.order_date, o.order_status, uf.file_name
from orders o left outer join uploaded_files uf on uf.oerder_id = o.order_id
order by o.order_id desc ) LIMIT 100
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