Re: if(), else() problem!

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Works like a charm!! I was trying something out with having a variable go
completely out of the functions & loops and print the "not found" message,
but I wasn't hitting it. You did!

// ^^^--- now tested ;)


On 10/6/06 1:52 PM, "Jochem Maas" <jochem@xxxxxxxxxxxxx> wrote:

> $msg = 'cannot open database!';
> if ($db = dbase_open("osm.dbf", 0)) {
>     $msg = 'database contains no records!';
>     if ($record_numbers = dbase_numrecords($db)) {
> $msg = 'number not found';
>         for ($i = 1; $i <= $record_numbers; $row =
> dbase_get_record_with_names($db, $i),$i++)
>             if ($row['PHONE'] == $thekey) { $msg = 'number found'; break; }
>     }
> }
> echo $msg;
> // ^^^--- untested
> 

Rahul S. Johari
Supervisor, Internet & Administration
Informed Marketing Services Inc.
500 Federal Street, Suite 201
Troy NY 12180

Tel: (518) 687-6700 x154
Fax: (518) 687-6799
Email: rahul@xxxxxxxxxxxxxxxxxxxx
http://www.informed-sources.com

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