On 10/5/06, intra_test@xxxxxxxx <intra_test@xxxxxxxx> wrote:
Using this string:
"{$var1: $var2}"
....of course it doesn't work as some might expect.
But why in the name of [whatever, too many to list] doesn't this one
below work?
"\{$var1: $var2}"
If \ is an escape character why does it also appear in the string output?
Why does the above \ escape {$var1 and not only the {?
Miserable.
First up:
http://uk2.php.net/manual/en/language.types.string.php#language.types.string.syntax.double
Excerpt:
Again, if you try to escape any other character, the backslash will be
printed too! Before PHP 5.1.1, backslash in \{$var} hasn't been
printed.
Then:
http://uk2.php.net/manual/en/language.types.string.php#language.types.string.parsing.complex
Excerpt:
Since you can't escape '{', this syntax will only be recognised when
the $ is immediately following the {. (Use "{\$" to get a literal
"{$").
Does that help?
HTH,
John W
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