On Wed, 4 Oct 2006 23:19:58 +0200, "Martin Bach Nielsen" <phpmaillist@xxxxxxxxxxxxx> wrote:
> Hi all.
>
>
>
> I have written a guestbook (I know, there's a ton out there), which until
> recently did not get any spam, so now I'm trying to remove the spam-ad by
> using preg_replace:
>
>
>
> $melding = preg_replace('/(<a href=\"http:\/\/[^^]+)/i', "This message is
> temporarily cut-off due to spam-suspicion.", $melding);
>
>
>
> However, this only makes the problem half-solved, since I also want any text
> before the link to be replaced with a message as stated above. The above
> line removes anything after '<a href=//'.
>
> Is there any way to make the above line to include anything before the <a
> href=// ?
>
>
>
> I have tried different options, and yes, I have read the php manual on
> preg_replace, but I might not have properly identified how to get the text
> in front modified.
>
>
>
> Thankful for any hints, tips, links, anything that helps :-)
>
>
>
> Regards,
>
> Martin Bach Nielsen
>
If you only want to replace the line including url(s) by a message, a
simple regular expression is enough.
<?php
$melding = "This is a spam.\n"
. "This is a <a href=\"http://www.example.com/\";>example</a> line.\n"
. "Another line.\n"
. "<a href=\"http://www.e.com/ads/show?n=123\";>123</a> (456)\n"
. "End Line.\n";
$melding = preg_replace("/.*?<a href=\"http:\/\/.+/i", "<This line is temporarily cut-off due to spam-suspicion.>", $melding);
echo $melding;
?>
The script above will output:
This is a spam.
<This line is temporarily cut-off due to spam-suspicion.>
Another line.
<This line is temporarily cut-off due to spam-suspicion.>
End Line.
--
Sorry for my poor English.
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