strip slashes from beginning and end of string in one expression

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PHP list.

This is another regular expression type of question.

The very handy PHP function trim() takes excess white space off the beginning and end of a string.

I'd like to be able to do the same thing, except instead of white spaces, trim excess slashes: /

So for example, all of these:
/this/that/
/this/that
this/that/
////////this/that////////////

... become:
this/that

There is also the chance of more than one slash occurring inside the desired text:
/this/that/this/that/

So that would also need to be accounted for. The above example should become:
this/that/this/that

I think I need to use preg_replace() for this, but, as ever, regular expressions completely throw me.

If I'm not mistaken, "#^/*#" should get me the first slash of the string, and more if there are more. And "#*/$#" should get me the last slash of the string, and more if there are more.

Can I test for the first and last slash in the same expression?

I think I either need something between the two that says "ignore what's in the middle", or and and/or statement to say "replace if this occurs at the end, or at the beginning, or both".

I've looked around and can't seem to find a way of connecting these in the same search. However, I'm sure that is because I'm not familiar enough with regular expressions to know what I'm looking at.

How would I connect "#^/*#" and "#*/$#" into one regular expression?

Thank you for your time and advice.

--
Dave M G
Ubuntu 6.06 LTS
Kernel 2.6.17.7
Pentium D Dual Core Processor
PHP 5, MySQL 5, Apache 2

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