On Tue, August 15, 2006 9:19 am, Brad Bonkoski wrote:
> Had this problem in the past, and always programmed around it, but
> wondering if there is an easier way.
>
> Good Example:
> Creating a setup for connecting to a mysql database. Want to do
> something simple to make sure they have entered a valid
> username/password for the database.
> So, the idea is something like:
> $rc = exec("mysql -u $user -p{$pass}", $output);
> The problem is one error, the stderr does not go to the output array,
> but rather to the screen.
>
> Previously I would redirect the stderr to a file, and then evaluate
> the
> contents of the file, but is there an easier way to get this into the
> PHP variable with no risk of having the output make it through to the
> screen?
In some OSes, in some shells, you can use:
mysql -u $user -p{$pass} 2>&1
The 2>&1 is special code for "redirect stdrrr (aka 2) to stdout (aka 2)"
Unless it's 2&>1 which I always forget which is which...
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