Jeffrey Sambells wrote:
OK I have a very strange bug:
In the middle of my script I have these two lines:
var_dump($test,$test2);
echo "'$test'=='$test2' is ".($test==$test2);
which is giving:
int(0) string(6) "Points"
'0'=='Points' is 1
I understand that PHP is loose typed and automatically does type
conversion but in the many years I've been using PHP (mostly v4) the
comparison had always converted to 'string' and in the case above
returned FALSE, not TRUE. It seems here they are comparing as integers
thus 'Points' evaluates to 0 and the comparison is TRUE.
I tried comparing in the reverse sequence ($test2==$test) and the same
occurred. It does work as expected if I have === but the rest of the
scirpt isn't type sensitive so I want NULL, 0, and empty string to still
maintain equality.
Any ideas why this is suddenly happening? I'm using PHP 5.1, and I
realize I could use other functions such as strval() in the comparison
however I've used similar logic in the past without problems.
Any help would be great.
Thanks
Jeff
No, the opposite is true; strings are always converted to integers in
such comparisons, as stated in TFM:
http://www.php.net/manual/en/language.operators.comparison.php
I'll quote it here:
"If you compare an integer with a string, the string is converted to a
number. If you compare two numerical strings, they are compared as
integers. These rules also apply to the switch statement."
In your case, it's a bug in your code; you should be using === to also
verify type, or casting $var1 to a string in your comparison.
Regards, Adam Zey.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
