Re: Re: A variable inside a variable?

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Please excuse-me.

That $ was putted by mistake.

I´sorry...

<tg-php@xxxxxxxxxxxxxxxxxxxxxx> escreveu na mensagem 
news:FF.F9.44237.05430A44@xxxxxxxxxxxxxxx
> You were on the right track, but this isn't going to work.. for a couple 
> reasons:
>
> $var = 1; # this is fine
> $var2 = "$var";  # $var2 == 1 at this point
> echo $$var2; # you're going to echo $1
>
> Putting $var in double quotes makes PHP evaluate it before assigning it to 
> $var2, so you won't get $var but the value of $var (1).
>
> If you did use single quotes, you'd get this:
>
> $var = 1; # this is fine
> $var2 = '$var';  # $var2 == '$var' (literal)
> echo $$var2; # you're going to echo $$var
>
> It seems like you might get $var2 evaluate to $var..  then with $$var have 
> it evaluate to 1, but doesn't look like PHP digs that deeply.  When I ran 
> it, I got NULL back.
>
> This might be what you were aiming for:
>
> $var = 1; # this is fine
> $var2 = 'var';  # remove the $..  then you can use single or double quotes
> echo $$var2; # $var == var,  $var == 1, this should output correctly
>
> Good lesson in 'gotchas' though.
>
> -TG
>
> = = = Original message = = =
>
> $var=1;
> $var2="$var";
> echo $$var2;
>
> It~ll echo the $var~s value.
>
> Hope it~ll help you.
>
>
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