Re: Calculating difference between two days

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Shouldn't be too difficult in PHP.

<?php
  $yesterday = date("m/d/y", mktime(0,0,0,date("m"), date("d") - 1, date("y")));
  $today = date("m/d/y");

  $secondsdiff = strtotime($today) - strtotime($yesterday);
  $minutesdiff = $secondsdiff / 60;
  $hoursdiff = $minutesdiff / 60;
  $daysdiff = $hoursdiff / 24;

  echo "Seconds difference: $secondsdiff<br>\n";
  echo "Minutes difference: $minutesdiff<br>\n";
  echo "Hours difference: $hoursdiff<br>\n";
  echo "Days difference: $daysdiff<br>\n";
?>


And if you want a larger example to play with, here's something I did a couple years ago (forgive the word wrapping and any unrefinedness.. it's something I whipped up as a test when someone asked a similar question back then).

There's bound to be some way to do it in SQL as well, but unless there's a specific function for it like the other example given by another member, then you're likely to write a lot of really ugly SQL code to tackle the problem.

Good luck!

-TG

<?php
  # Standard format dates and times
  $startdate = "04/12/04";
  $starttime = "13:05:01";
  
  $enddate = "10/14/04";
  $endtime = "13:05:01";
  
  # Break apart dates and times for mktime
  list($smonth,$sday,$syear) = explode("/",$startdate);
  list($emonth,$eday,$eyear) = explode("/",$enddate);
  list($shour,$sminute,$ssecond) = explode(":",$starttime);
  list($ehour,$eminute,$esecond) = explode(":",$endtime);
  
  # Number of seconds in each timeframe, 1 month = 30 days
  $secondsequiv array("Years"=>31536000,"Months"=>2592000,"Days"=>86400,"Hours"=>3600,"Minutes"=>60);
  
  # How many seconds between two dates/times
  $daydiff = mktime($ehour,$eminute,$esecond,$emonth,$eday,$eyear) -
  mktime($shour,$sminute,$ssecond,$smonth,$sday,$syear);
  
  if ($daydiff < 0) { $daydiff *= -1; $negative = TRUE; }
  
  # Just to make sure I didn't use $remainder somewhere else in my script and forgot
  if (isset($remainder)) unset($remainder);
  
  # Cycle through timeframes checking to see if number is large enough to be a full year/month/day/etc
  # If so, find out how many and store remainder for further processing
  # If not, set to zero and continue processing
  foreach ($secondsequiv as $timeframe=>$seconds) {
    if (isset($remainder)) { $checkvalue = $remainder; } else { $checkvalue = $daydiff; }
    if ($checkvalue >= $seconds) {
      $daydiffarr[$timeframe] = floor($checkvalue/$seconds);
      $remainder = $daydiff % $seconds;
    } else {
      $daydiffarr[$timeframe] = 0;
    }
  }
  
  # If $reminder is never used, then we're dealing with less than a minute's worth of time diff
  if (isset($remainder)) {
    $daydiffarr["Seconds"] = $remainder;
  } else {
    $daydiffarr["Seconds"] = $daydiff;
  }
  
  # Display results
  if ($negative) echo "NEGATIVE!!<br>\n";
  foreach ($daydiffarr as $timeframe=>$count) {
    echo "$timeframe = $count<br>\n";
  }
?> 

= = = Original message = = =

Hi,
I need to calculate no. of days between two dates, actually between date
stored in DB and today's date.

Does anybody has an example I can use?

I found an example on
http://www.developertutorials.com/tutorials/php/calculating-difference-between-dates-php-051018/page1.html

but function gregoriantojd() doesn't work for me
Fatal error: Call to undefined function: gregoriantojd()

Found this:
Please read the manual:
  http://www.php.net/manual/en/ref.calendar.php
You need to either compile the extension in or load it.
Since you provided no details about your situation at all,
I cannot help you further.
on
http://bugs.php.net/bug.php?id=10151&edit=1


Thanks on any help.

-afan


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