Re: When is "z" != "z" ?

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2006/6/6, Robert Cummings <robert@xxxxxxxxxxxxx>:

On Tue, 2006-06-06 at 09:46, Martin Alterisio wrote:
> 2006/6/6, Robert Cummings <robert@xxxxxxxxxxxxx>:
>
> > In C++ they do leave it to the coder, and well, we all know what a
mess
> > it can be deciphering overloaded operators in C++ (or maybe we ALL
> > don't). At any rate, the PHP overlords made a choice, and IMHO the
best
> > choice. For such a fringe issue I don't see what the argument is all
> > about. If you want the functionality you get in C by incrementing a
> > char, then use the chr() function on an integer.
> >
> >
> You're right about ++ operator not to be considered a math operator, my
> mistake. What I should have said is that the usual connotation and
expected
> behaviour of ++ and the comparison operators is to give iteration
> capabilities to a certain data type, as used in a for statement. For
that to
> happen certain constrains must be true for these operators, one of them
> being: any < ++any, which is not true for the way these operators behave
in
> php.

You must have missed this post:

http://marc.theaimsgroup.com/?l=php-general&m=114945456908350&w=2


Yes, I haven't read that post. That algorithm has an error, an overflow on a
signed char, and that's implementation issue not a design issue.

PS: It's a little bit rude to say "you *must* have missed" but I understand
that it wasn't your intention.

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