Chris,
Thank you for replying.
$object = new $className();
Is this possible?
If in doubt, test it out ;)
Yes, it will work.
Oh, that's actually the code I can use? I just wrote it as an
explanatory aid, not thinking that it could be literally done like that.
I assumed there was a specific command I was missing.
Well, anyway, I guess I've stumbled on the right syntax. Thank you for
pointing it out to me.
--
Dave M G
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