Ministério Público wrote:
I showed where the problem is and after var_dump all I get is NULL. I
just sent the code cause I thought it would be easier to see it in
context, not to make somebody trawl trough it. If its not an array how
to find out what it is? What can I do about it?
Put debug lines throughout your code and see where it breaks.
eg:
echo "at line " . __LINE__ . ", var is " . gettype($JSFileExtArray) .
"<br/>";
do that every 20 lines and then narrow the problem down from there.
--
Postgresql & php tutorials
http://www.designmagick.com/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
