Ooopps.
I just did have array too many. This did the append corretly:
$arr["Team$cur"] = array(id => $id, sort => $srt, jnimi => $nimi);
-Will
""Joe Wollard"" <joe.wollard@xxxxxxxxx> kirjoitti
viestissä:4b95b27e0604252357y224eb6e4xf351bbdb4593bdb3@xxxxxxxxxxxxxxxxx
Will,
Seems to me like you've just done it! Here's another way of doing it that
will utilize mysql_fetch_assoc() to allow your query to dictate the elements
of the array. Keep in mind, I haven't tested this, but since I'm not
entirely sure what you are asking the list, I'll offer it anyway ;-)
<?php
/*...do connection stuff here...*/
$sql = "SELECT sortteri,jouk_id,jouk_nimi FROM x_table ORDER BY sortteri
ASC";
$result = mysql_query($sql);
$num = mysql_num_rows($result);
$Team = null; //We'll fill this up later - gotta love PHP ;-)
// loop over each row in the result set
for($i=0; $i<$num; $i++){
$tmp = mysql_fetch_assoc($result);
// loop over each column in the current row
while(list($key, $val) = each($tmp))
$Team[$key][$i] = $val;
}
// display the contents of the $Team array
print_r($Team);
?>
On 4/26/06, William Stokes <kalles@xxxxxxxxxxxxx> wrote:
>
> Hello,
>
> Can someone please help me to put the results of a query to an array.
> Never
> done this before:
>
> $sql = "SELECT sortteri,jouk_id,jouk_nimi FROM x_table ORDER BY sortteri
> ASC";
> $result = mysql_query($sql);
> $num = mysql_num_rows($result);
> $cur = 1;
>
> //create empty array that contains an array before loop
> $arr = array("Team" => array());
>
> while ($num >= $cur) {
> $row = mysql_fetch_array($result);
> $id = $row["jouk_id"];
> $srt = $row["sortteri"];
> $nimi = $row["jouk_nimi"];
>
> //append values to the array
> $arr = array("Team$cur" => array(0 => $id, 1 => $srt, 2 => $nimi));
>
> $cur++;
> }
>
> Thanks
> -Will
>
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