At 7:31 PM -0700 4/10/06, Ray Hauge wrote:
>
I believe you're thinking more of the C++ style of returning by reference.
This article should help explain how references work, and how to return
references... most specifically check the "Returning References" section.
> http://www.php.net/manual/en/language.references.php
nevermind... I what I read and what was actually written seem to have been two
entirely different things ;) Still good info though.
--
Ray Hauge
Ray:
It was an interesting read -- but, I found it, and the comments, confusing.
The difference I was able to get was I know if you display a C
pointer, would will see a memory address -- if you display a PHP
reference, you will see the value. As such, one is a memory address
and the other is a symbol table alias -- but they still seem to work
the same. I haven't seen a working difference yet.
Additionally, what I don't get is this:
<?php
$a = 10;
echo("$a <br/>");
ref1(&$a);
echo("$a <br/>");
$a = 10;
echo("$a <br/>");
ref2($a);
echo("$a <br/>");
$a = 10;
echo("$a <br/>");
ref3($a);
echo("$a <br/>");
?>
<?php
function ref1($a)
{
$a--;
}
?>
<?php
function ref2(&$a)
{
$a--;
}
?>
<?php
function &ref3($a)
{
$a--;
}
?>
The first two functions work as I would expect. The last one is shown
in the documentation, but doesn't work as I expected. There doesn't
appear to be any difference between ref1 and ref3 -- so what's with
the "ampersand" in &ref3? What is an ampersand supposed to mean/do
when it precedes a function?
Thanks.
tedd
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