It's not that it's not allowed, it's that it should be done
differently. You should make the function accept a reference in the
definition, not pass in a reference to the function.
The manual page has a good, simple example on what to do.
http://www.php.net/manual/en/language.references.pass.php
Chris:
Interesting. One would think (at least I do) it should be the other way around.
Using the example given at the link above:
<?php
function foo(&$var)
{
$var++;
}
$a=5;
foo($a);
// $a is 6 here
?>
We have one function that works one way.
<?php
function foo($var)
{
$var++;
}
$a=5;
foo(&$a);
// $a is 6 here
?>
However, doing it this way, the function can serve two purposes. I
can send it a reference or I could send it a value. I know that in
this function a value doesn't do anything, but it could if the
function was different.
Plus, in the first function, I can't send it a reference (i.e., a
reference to a reference?).
What's short reasoning for this being recommended this way? What am I
not seeing?
tedd
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