RE: Parsing variables within string variables

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Or change the quote style to double (")

Just another option

Dan

(If I'm right this time... I really can't afford 88AUD/hr... :) )
-------------------
http://chrome.me.uk
 

-----Original Message-----
From: Jay Blanchard [mailto:jblanchard@xxxxxxxxxx] 
Sent: 07 April 2006 18:12
To: David Clough; php-general@xxxxxxxxxxxxx
Subject: RE:  Parsing variables within string variables

[snip]

I have a variable containing a string that contains the names of 
variables, and want to output the variable with the variables it 
contains evaluated. E.g. 

   $foo contains 'cat'
   $bar contains 'Hello $foo'

and I want to output $bar as 

   Hello cat

The problem is that if I use

   echo $bar

I just get

   Hello $foo
[/snip]

$bar = 'Hello' . $foo;

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