I've been bashing my head against the wall on this, and would be glad of help to stop. I have a variable containing a string that contains the names of variables, and want to output the variable with the variables it contains evaluated. E.g. $foo contains 'cat' $bar contains 'Hello $foo' and I want to output $bar as Hello cat The problem is that if I use echo $bar I just get Hello $foo Note that $bar is loaded from a database query, so I can't control its contents: I just have to parse it. Any help appreciated. David. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
