Jim Lucas wrote:
Jasper Bryant-Greene wrote:
Jochem Maas wrote:
[snip]
you guess wrong :-) .. I couldn't resist testing it:
php -r '
class T { private $var = array();
function __set($k, $v) { $this->var[$k] = $v; }
function __get($k) { var_dump($k); }
}
$t = new T;
$t->arr = array();
$t->arr["a"] = 1;
echo "OUTPUT: \n"; var_dump($t->arr); var_dump($t->arr["a"]);
var_dump($t);
'
[snip]
Code:
<?php
class T {
private $array = array();
public function __get( $key ) {
return $this->array[$key];
}
public function __set( $key, $value ) {
$this->array[$key] = $value;
}
}
$t = new T;
$t->insideArray = array();
$t->insideArray['test'] = 'testing!';
var_dump( $t );
?>
Output:
object(T)#1 (1) {
["array:private"]=>
array(1) {
["insideArray"]=>
array(1) {
["test"]=>
string(8) "testing!"
}
}
}
Dont know if you guys see the MAJOR difference between your code, so I
will point it out.
Jasper did this
function __get($k) {
var_dump($k);
}
Uhm, no I didn't. Jochem did :)
Jochem did this
public function __get( $key ) {
return $this->array[$key];
}
No, I did that.
First off, the required public before the function call was not
included, secondly, Jasper is var_dumping the key of the array, not the
array it self.
Public is not required. I always put it regardless, but if you leave it
off then PHP defaults to public for compatibility reasons.
Jochem's code, which behaves incorrectly, does var_dump. Mine just
returns the array key as you would expect. That's why Jochem's doesn't
behave correctly with arrays.
--
Jasper Bryant-Greene
General Manager
Album Limited
http://www.album.co.nz/ 0800 4 ALBUM
jasper@xxxxxxxxxxx 021 708 334
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