On 21/03/06, sathyashrayan <foraci@xxxxxxxxx> wrote: > > ----- Original Message ----- > From: "Dan Parry" <dan@xxxxxxxxxxxxxxxxxxx> > To: "'sathyashrayan'" <foraci@xxxxxxxxx>; <php-general@xxxxxxxxxxxxx> > Sent: Tuesday, March 21, 2006 6:12 PM > Subject: RE: Inserting data at runtime (php,mysql) > > > > [snip] > > $conn=mysql_connect(" ");/*with the required parameters*/ > > if(!conn) <<< > > { > > [/snip] > > > > You are testing conn in your if condition... should that not be $conn? > > > > No if conn evaluates to false then error. Yeah, but it should be $conn, not conn. PHP treats conn as an unquoted string which evaluates to true, so it's quite possible that your mysql_connect() is failing and you're not detecting it. $ php -r 'if (conn) print "Connected...\n";' Connected... You're not checking that you've managed to open the file - if you've got error_reporting turned down low then you'll miss the warnings from that. You've also got problems with the while($funct_var) loop - that return statement is all that's stopping it looping infinitely and it's still almost certainly not what you want. -robin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php