[snip]
> Try;
>
> $foo = preg_replace($find,$replace,$partFormula);
> return $foo
Unfortunately no. I also tried making the formula look like this:
<?php (36.00000*58.00000)/144 ?>
and returning it with:
eval('?>' . $a . '<?php ');
[/snip]
Let's do an experiment. Place these two lines of code in a page, then load
it in a browser;
<?php
$foo = (36.00000*58.00000)/144;
echo $foo;
?>
works fine for me. If you change
<?php (36.00000*58.00000)/144 ?>
to
<?php echo (36.00000*58.00000)/144; ?>
it also works.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
