WTF are you smoking Al?
Al wrote:
Jochem Maas wrote:
Al wrote:
However....
For loops:
$new_array= array();
foreach($old array as $value){
$new_array= $value:
}
Otherwise, all you'll get it the last assignment of $new_array as a
variable, not an array.
which is exactly what you get if yuou run the code above - after
the foreach loop $new_array will be set to the value of the
last item of $old_array.
regardless of whether you init the var you still have to
use the square-bracket notation to add items to the array.
You can also use;
foreach($old array as $value){
$new_array[]= $value:
}
Taint so Jochem. Try it.
1. using the word 'Taint' there makes no sense.
2. secondly your example code didn't even parse.
3. I don't need to bloody try it, but just for you I did - so now you
can explain the following ouput (i.e. that after the loop has run $new_array
is equal to the string 'A'):
PHP 5.0.4 (cli) (built: Aug 16 2005 15:29:25)
moulin@moulin~ -- Wed Dec 14 17:21:47
$> php -r '
$> $old_array = range(A,E); $new_array = array();
$>
$> echo "BEFORE:\n";
$> var_dump($new_array, $old_array);
$>
$> foreach($old_array as $value) { $new_array = $value; }
$>
$> echo "AFTER:\n";
$> var_dump($new_array, $old_array);
$> '
BEFORE:
array(0) {
}
array(5) {
[0]=>
string(1) "A"
[1]=>
string(1) "B"
[2]=>
string(1) "C"
[3]=>
string(1) "D"
[4]=>
string(1) "E"
}
AFTER:
string(1) "E"
array(5) {
[0]=>
string(1) "A"
[1]=>
string(1) "B"
[2]=>
string(1) "C"
[3]=>
string(1) "D"
[4]=>
string(1) "E"
}
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