Hi,
Sorry, i do have the table name.
It just passed me while transcripting.
The code is:
---
$query = "SELECT COUNT (login) FROM formacao WHERE login = '$login'";
$result = mysql_query($query);
mysql_fetch_row($result);
---
It works perfectly on MySQL prompt.
Regards,
Mário Gamito
Colin Shreffler wrote:
It looks to me like you forgot to specify the table in your query:
SELECT COUNT (login) FROM <TABLENAME GOES HERE> WHERE login = '$login'
Hi,
Why this doesn't work ?
---
$query = "SELECT COUNT (login) FROM WHERE login = '$login'";
$result = mysql_query($query);
mysql_fetch_row($result);
---
It gives me
Warning: mysql_fetch_row(): supplied argument is not a valid MySQL
result resource in /var/www/html/registar_action.php on line 22
Any help would be apreciated.
Warm Regards,
Mário Gamito
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Thank you,
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