Are you positive the second file exists? If you have access to your logs, you may want to check for an error. Maybe you don't have permission to access the file? You might also try urlencoding the filename before passing it to your function. On a lighter note, If you're using PHP version 4 and you just want to read the entire contents of the file into one variable, you should consider using file_get_contents(). It's a little less code to type, and is more efficient PHP Documentation is here: http://php.net/file_get_contents. -- Sincerely, A.J. Brown ""ËÎçù"" <sandysong28@xxxxxxxxxxxx> wrote in message news:20050928132259.60934.qmail@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx > Hi everyone > I`m a phper from chinese, I`v got a problem when opening files. In the web > server there are two files named A.zip and B.zip, when I open them with > "$fp=fopen("http://mysite.com/A.zip","r";);" and > "$fp1=fopen("http://mysite.com/B.zip","r";);", the first file was opened > correctly but the second encounter an warning: "failed to open stream: > HTTP request failed! HTTP/1.1 200 OK in ...." and filed to open the file. > So, give me some help please. > > __________________________________________________ > ¸Ï¿ì×¢²áÑÅ»¢³¬´óÈÝÁ¿Ãâ·ÑÓÊÏä? > http://cn.mail.yahoo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
